本文小編為大家詳細(xì)介紹“如何用Android的opencv實(shí)現(xiàn)多通道分離與合并”,內(nèi)容詳細(xì),步驟清晰,細(xì)節(jié)處理妥當(dāng),希望這篇“如何用Android的opencv實(shí)現(xiàn)多通道分離與合并”文章能幫助大家解決疑惑,下面跟著小編的思路慢慢深入,一起來學(xué)習(xí)新知識吧。
public static void split(Mat m, Listmv)
參數(shù)一:m,待分離的多通道圖像
參數(shù)二:mv,分離后的單通道圖像
override fun onCreate(savedInstanceState: Bundle?) { super.onCreate(savedInstanceState) mBinding = DataBindingUtil.setContentView(this, R.layout.activity_channel_split_merge) mBgr = Utils.loadResource(this, R.drawable.test) val imgList = mutableListOf() Core.split(mBgr, imgList) mChannelB = imgList[0] mChannelG = imgList[1] mChannelR = imgList[2] }
public static void merge(Listmv, Mat dst)
參數(shù)一:mv,需要合并的圖像數(shù)組,其中每個圖像必須擁有相同的尺寸和數(shù)據(jù)類型
參數(shù)二:dst,合并后輸出的圖像,與mv[0]具有相同的尺寸和數(shù)據(jù)類型,通道數(shù)等于所有輸入圖像的通道數(shù)總和
private fun showBGZero() { val zero = Mat.zeros(mBgr.rows(), mBgr.cols(), CvType.CV_8UC1) val list = mutableListOf() list.add(zero) list.add(zero) list.add(mChannelR) val result = Mat() Core.merge(list, result) showMat(result) result.release() } private fun showBRZero() { val zero = Mat.zeros(mBgr.rows(), mBgr.cols(), CvType.CV_8UC1) val list = mutableListOf () list.add(zero) list.add(mChannelG) list.add(zero) val result = Mat() Core.merge(list, result) showMat(result) result.release() } private fun showGRZero() { val zero = Mat.zeros(mBgr.rows(), mBgr.cols(), CvType.CV_8UC1) val list = mutableListOf () list.add(mChannelB) list.add(zero) list.add(zero) val result = Mat() Core.merge(list, result) showMat(result) result.release() } private fun showSwitchBR() { val zero = Mat.zeros(mBgr.rows(), mBgr.cols(), CvType.CV_8UC1) val list = mutableListOf () list.add(mChannelR) list.add(mChannelG) list.add(mChannelB) val result = Mat() Core.merge(list, result) showMat(result) result.release() }
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