用C語言計(jì)算分段函數(shù)

#include "stdio.h"

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#includemath.h

void main()

{

double x,y,f,h;

printf("請輸入x:\n");

scanf("%lf",x);

printf("請輸入y:\n");

scanf("%lf",y);

if((x=0)(y0))

f=2*pow(x,2)+3*x+1/x+y;

else if((x=0)(y=0))

f=2*x*x+3*x+1/x+y*y;

else

f=3*sin(x+y)/2/pow(x,2)+3*x+1;

printf("x=%lf,y=%lf,f=%lf\n",x,y,f);

h=pow(x,2);

printf("%lf",h);

}

怎么用c語言編程一個(gè)分段函數(shù)？

#include

int?main()

{

int?x,y;

scanf("%d",x);

if(0xx10)?y=3*x+2;

else

{if(x=0)?y=0;

else

{if?(x0)?y=x*x;

else?printf("go?die\n");

}

}

printf("%d",y);

return?0;

}該程序的分段函數(shù)如下:

f(x)=3x+2? (0x10)

f(x)=1???????? (x=0)

f(x)?=?x*x??? (x0)

#include stdio.h

#include math.h

void main()

{

float x;

double y;

printf("Please input the value of x:");

scanf("%f",x);

if(x=-10x=4)

{

y=fabs(x-2);

printf("y=%.2f\n",y);

}

else if(x=5x=7)

{

y=x+10;

printf("y=%.2f\n",y);

}

else if(x=8x=12)

{

y=pow(x,4);

printf("y=%.2f\n",y);

}

else

printf("No answer\n");

}

C語言計(jì)算分段函數(shù)

1. 代碼如下，3）需要實(shí)際運(yùn)行時(shí)輸入測試

int main(void)

{

double x, y, f;

printf("Please input 2 double number in the form of x y:\n");

scanf("%lf%lf", x, y);

if(x=0 y0)

f = 2*x*x + 3*x +1/(x+y);

else if(x=0 y=0)

f = 2*x*x + 3*x +1/(1+y*y);

else

f = 3*sin(x+y)/(2*x*x) + 3*x + 1;

printf("x=%lf, y=%lf, f(x, y)=%lf\n", x, y, f);

return 0;

}

2.代碼如下

#include stdio.h

#includemath.h

int main(void)

{

double x, y, f;

printf("Please input 2 double number in the form of x y:\n");

scanf("%lf%lf", x, y);

if(x=0)

{

if(y0)

f = 2*x*x + 3*x +1/(x+y);

else

f = 2*x*x + 3*x +1/(1+y*y);

}

else

f = 3*sin(x+y)/(2*x*x) + 3*x + 1;

printf("x=%lf, y=%lf, f(x, y)=%lf\n", x, y, f);

return 0;

}

3.代碼如下

#include stdio.h

int main(void)

{

int score = 0;

printf("Please input a score between 0-100:\n");

scanf("%d", score);

if(score0 || score100)

printf("Wrong input of score!\n");

else if(score=90 score=100)

printf("A\n");

else if(score=80 score=89)

printf("B\n");

else if(score=70 score=79)

printf("C\n");

else if(score=60 score=69)

printf("D\n");

else

printf("E\n");

return 0;

}