怎么用c語(yǔ)言編程一個(gè)分段函數(shù)？

#include

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int?main()

{

int?x,y;

scanf("%d",x);

if(0xx10)?y=3*x+2;

else

{if(x=0)?y=0;

else

{if?(x0)?y=x*x;

else?printf("go?die\n");

}

}

printf("%d",y);

return?0;

}該程序的分段函數(shù)如下:

f(x)=3x+2? (0x10)

f(x)=1???????? (x=0)

f(x)?=?x*x??? (x0)

#include stdio.h

#include math.h

void main()

{

float x;

double y;

printf("Please input the value of x:");

scanf("%f",x);

if(x=-10x=4)

{

y=fabs(x-2);

printf("y=%.2f\n",y);

}

else if(x=5x=7)

{

y=x+10;

printf("y=%.2f\n",y);

}

else if(x=8x=12)

{

y=pow(x,4);

printf("y=%.2f\n",y);

}

else

printf("No answer\n");

}

c語(yǔ)言編程分段函數(shù)。

#includestdio.h

void?main()

{?

float?x,y;

scanf("%f",x);

if(x0)

y=x*x;

else?if(x==0)

y=2*x-1;

else?

y=-3*x*x-1?;//這里少個(gè)分號(hào)

printf("%.2f",y);

}

C語(yǔ)言編程題：編程序求如下分段函數(shù)：

#include stdio.h

#include math.h

double fun(double x)

{

if (x=0)return(-x+3);

else if(x1)return 1+x*x;

else ?return ?2*x+sqrt(x);

}

int main()

{

double x;

scanf("%lf",x);

printf("y=%lf \n",fun(x));

system("pause");

return 0;

}