大神進(jìn)：MYSQL各科成績(jī)前三名

select * from

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(select Student.S#,Sname,Sage,Ssex,SC.C#,score,Cname

from SC inner join Student on SC.S#=Student.S#

inner join Course on Course.C#=SC.C#) as t

where exists(

select count(1) from t as d

where C#=d.C# and score d.score

having count(1)3

)

sql語句 每科成績(jī)的前三名

可以用row_number函數(shù)來解決。

1、創(chuàng)建測(cè)試表，插入數(shù)據(jù)：

create table sc

(id int,

name varchar(20),

class varchar(20),

score int);

insert into sc values (1,'badkano','一年一班',100)

insert into sc values (2,'百度知道團(tuán)長','一年一班',99)

insert into sc values (3,'du小短','一年一班',95)

insert into sc values (4,'du小小動(dòng)','一年一班',97)

insert into sc values (5,'du小智','一年一班',80)

insert into sc values (6,'呂布','一年二班',67)

insert into sc values (7,'趙云','一年二班',90)

insert into sc values (8,'典韋','一年二班',89)

insert into sc values (9,'關(guān)羽','一年二班',70)

insert into sc values (10,'馬超','一年二班',98)

2、查詢每個(gè)班級(jí)的前三名，可用語句：

select * from

(select row_number() over (partition by class order by score desc) 排名,* from sc) t

where 排名=3 order by class asc,score desc

Mysql 分組以后取每組的前三名數(shù)據(jù)

Try this one,should be fine

下面這個(gè)已經(jīng)有排序了哦，不行么？

SELECT uid, group_concat(subject)

FROM (SELECT id, uid, subject

FROM (SELECT id, uid, subject,

(SELECT COUNT(*)

FROM t_subject

WHERE uid = t.uid

AND subject = t.subject) RK

FROM t_subject t) t1

WHERE rk = 3) t2

GROUP BY uid

多了個(gè)a.原來

或者你直接用個(gè)substring()得了。。。