VB.NET 2維數(shù)組排序排序和賦值問題

窗體上添加3個標(biāo)簽，1個按鈕，在按鈕的單擊事件里寫代碼，如下：

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Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click

Dim a(,) As Integer = {{5, 6}, {1, 3}, {8, 9}, {72, 1}, {63, 4}}

Dim Temp As Integer

Dim i As Integer

Dim j As Integer

Dim x As Integer

Dim y As Integer

'顯示排序前的數(shù)據(jù)

Label1.Text = "排序前數(shù)據(jù)：" vbCrLf

For i = 0 To 4

Label1.Text = Label1.Text a(i, 0) " " a(i, 1) vbCrLf

Next

For i = 0 To 3

For j = i + 1 To 4

If a(i, 0) a(j, 0) Then

Temp = a(i, 0)

a(i, 0) = a(j, 0)

a(j, 0) = Temp

Temp = a(i, 1)

a(i, 1) = a(j, 1)

a(j, 1) = Temp

End If

Next

Next

'顯示排序前的數(shù)據(jù)

Label2.Text = "排序后數(shù)據(jù)：" vbCrLf

For i = 0 To 4

Label2.Text = Label2.Text a(i, 0) " " a(i, 1) vbCrLf

Next

'把第3行元素賦予X,Y

x = a(2, 0)

y = a(2, 1)

'輸出X,Y

Label3.Text = "X=" x vbCrLf "Y=" y

End Sub

vb.net 怎么使用指針對數(shù)組快速賦值賦值

數(shù)組好像沒有快速賦值吧，或者你再把問題再清楚一點。

語句執(zhí)行時間倒是可以做到。在語句前

Dim oldTime As Date = Now

在過程語句后加

Dim newTime As Date = Now

Dim differenceInSeconds As Long = DateDiff(DateInterval.Second, oldTime, newTime)

textbox1.text= "共用了:" differenceInSeconds "秒!"

vb.net 數(shù)組

vb.net已經(jīng)去掉了控件數(shù)組這個類，不過有個代替該方式的一個屬性：Tag，你可以把這些關(guān)聯(lián)的Tag屬性設(shè)置為同一標(biāo)記，如：a。然后遍歷所有的checkbox并且tag為a的則選定：Protected Sub chkAll_Click() For Each ctl As Control In Me.Controls ''如果checkbox在一個容器里，比如groupbox，那可以用groupbox.controls

If ctl.GetType().Name.ToLower() = "checkbox" Then

CType(ctl, CheckBox).Checked = CheckBox3.Checked

End If

NextEnd Sub

vb.net的問題，編程實現(xiàn)將一個3*4的二維數(shù)組A，轉(zhuǎn)置后在textbox中顯示

for i = 0 to 3

textbox_未知.text = a(i,1) a(i,2) a(i,3) a(i,4) vbcrlf

next

如果我吧長寬弄反了自行轉(zhuǎn)正,

如果要間隔,請插入 VBtab

vb.net數(shù)組逆序的程序

參考

#includestdio.h

int main()

{int n,i,j,t,a[200];

printf("數(shù)組中數(shù)的個數(shù)：");

scanf("%d",n);

printf("數(shù)組中的數(shù)：\n");

for(i=0;in;i++)

{

a[i]=i+1;

printf("%d ",a[i]);

}

for(i=0,j=n-1;ij;i++,j--)

{t=a[i];a[i]=a[j];a[j]=t;}

printf("\n逆序后的數(shù)組：\n");

for(i=0;in;i++)

printf("%d ",a[i]);

printf("\n");

getch();

return 0;

}