select class,total,name from (select *,ywsc+sxsc as total from st ORDER BY total DESC) b
按需網(wǎng)站策劃可以根據(jù)自己的需求進(jìn)行定制,成都網(wǎng)站制作、網(wǎng)站設(shè)計(jì)構(gòu)思過(guò)程中功能建設(shè)理應(yīng)排到主要部位公司成都網(wǎng)站制作、網(wǎng)站設(shè)計(jì)的運(yùn)用實(shí)際效果公司網(wǎng)站制作網(wǎng)站建立與制做的實(shí)際意義
where
not EXISTS(select * from (select *,ywsc+sxsc as total from st ORDER BY total DESC) c where c.class=b.class and b.total c.total GROUP BY c.class HAVING COUNT(*)2 )
ORDER BY b.class,b.total DESC
SELECT * FROM 表 LIMIT 0, 3LIMIT 接受一個(gè)或兩個(gè)數(shù)2113字參數(shù)。參數(shù)必須是5261一個(gè)整數(shù)常量。如果給定4102兩個(gè)參數(shù),第一1653個(gè)參數(shù)指定第一個(gè)返回記錄行的偏移量,第二個(gè)參數(shù)指定返回記錄行的最大數(shù)目。初始記錄行的偏移量是 0(而不是 1)
select scrname,stucount from scrtab
select top 3 scrname,stucount from scrtab order by stucount
先按人數(shù)排序,然后在查出前三個(gè)
sql server查詢前n條記錄:
因?yàn)閕d可能不是連續(xù)的,所以不能用取得10
上面那條答案應(yīng)該是可以的啊,可能是看起來(lái)復(fù)雜了點(diǎn)吧,我自己試過(guò)是沒(méi)問(wèn)題的:
SELECT t1.sno,t1.cno,Score
FROM SC t1
WHERE EXISTS
(SELECT COUNT(1)
FROM SC
WHERE t1.cno= cno AND t1.scorescore
HAVING COUNT(1)3)
ORDER BY t1.cno,score DESC
另外還有一種類似的寫法:
SELECT t1.sno,t1.cno,Score
FROM SC t1
WHERE
(SELECT COUNT(cno)
FROM SC
WHERE t1.cno= cno AND t1.scorescore)3
ORDER BY t1.cno,score DESC