sqlserver通過查詢表記錄取得記錄總數(shù)的存儲(chǔ)過程怎么書寫啊。

你是說所有表的總記錄數(shù)嗎？給你個(gè)樣例你看下有沒有幫助

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SELECT p.object_id,OBJECT_NAME(p.object_id),p.rows,t.*

FROM sys.partitions AS p

INNER JOIN sys.tables AS t ON p.[object_id] = t.[object_id]

INNER JOIN sys.schemas AS s ON t.[schema_id] = s.[schema_id]

WHERE p.index_id IN (0, 1)

AND t.type='U'

如何統(tǒng)計(jì)sqlserver多張表的數(shù)據(jù)總數(shù)

SqlServer中這樣統(tǒng)計(jì):

select name from sysobjects where xtype='U'

要知道總數(shù)的話就簡(jiǎn)單了：

select count(*) from sysobjects where xtype='U'

Oracle中這樣查詢：

Select * From user_tables;

sqlserver怎么實(shí)現(xiàn)同一個(gè)表中多個(gè)count查詢并且分組并且統(tǒng)計(jì)總數(shù)

可以有兩種解決方法，

所需工具：SQL

查詢兩個(gè)count的方法1:

SELECT paperName , COUNT (1) AS 總題數(shù) , sum (CASE WHEN statu = 1 THEN 1 ELSE 0 END) AS 審核題數(shù)FROM questionGROUP BY paperNme

查詢兩個(gè)count的方法2:

select s.總題數(shù), s.審核題數(shù), s.paperNamefrom (select COUNT(1) as 總題數(shù), case when status = 1 then count(1) else 0 end as 審核題數(shù), paperNamefrom question--where papername in (select distinct paperName from question), 這個(gè)條件可以不要了group by paperNme, stauts -- status也要作為分組字段，因?yàn)樵赾ase中有使用) s