C語言中如何將小數(shù)點部分一位一位取出？

int n=5;

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double x=3.141592654;

while(n0) //取出小數(shù)后n位

{

x=x*10; //更新x值，把小數(shù)點后第一位放在個位上

printf("%d\n",(int)x%10); //int強制把double轉(zhuǎn)換成int，因為求余必須為int類型， //而%10求余，是求個位上的數(shù)字

i--;

}

請問 單片機C語言里的bit定義函數(shù)和變量時怎么回事，怎么用bit？謝謝！@

bit是二進制的位的意思 如果你要操作位 最好用位運算符 等

C語言編程：編寫函數(shù)getbit(n,k),求出n從右邊開始的第k位，在主函數(shù)中輸入數(shù)據(jù)并調(diào)用結(jié)果。

128的二進制表示：?10000000

從右往左數(shù)第八位是1

答案也簡單：

C語言版:

int?getbit(int?n,?int?k){

return?(n(k-1))??1;

}

C語言取位函數(shù)的實現(xiàn)

我有點沒搞明白（45、81、673938）取最后一位是怎么得出5138的，不是518嗎？

但還是隨便寫一下吧

#include?stdio.h

#include?stdlib.h

int?getLastBit(int?number);

int?main()

{

int?i?=?0,?n?=?0;

int?number?=?0,?newnumber?=?0;

printf("輸入整數(shù)個數(shù)：");

scanf("%d",?n);

for(i?=?1;?i?=?n;?i++)

{

scanf("%d",?number);

newnumber?*=?10;????????????

newnumber?+=?getLastBit(number);????

}

printf("新整數(shù)是：%d\n",?newnumber);

return?0;?

}

int?getLastBit(int?number)

{

if(number?=?0)

{

printf("錯誤！\n");

exit(1);

}

else

return?number%10;

}

c語言的bit類型

C語言中bit類型是“位”數(shù)據(jù)類型，一般在嵌入式軟件中應(yīng)用較多，用于IO口的控制，可以是單獨申明位變量，也可以申請位結(jié)構(gòu)數(shù)據(jù)類型，比如：

struct?st_flash?{???????????????????????????????????????????/*?struct?FLASH?*/

union?{???????????????????????????????????????/*?FLMCR1???????*/

unsigned?char?BYTE;????????????/*??Byte?Access?*/

struct?{??????????????????????????????????/*??Bit??Access?*/

unsigned?char?FWE?:1;??????/*????FWE???????*/

unsigned?char?SWE1:1;??????/*????SWE1??????*/

unsigned?char?ESU1:1;??????/*????ESU1??????*/

unsigned?char?PSU1:1;??????/*????PSU1??????*/

unsigned?char?EV1?:1;??????/*????EV1???????*/

unsigned?char?PV1?:1;??????/*????PV1???????*/

unsigned?char?E1??:1;???????/*????E1????????*/

unsigned?char?P1??:1;???????/*????P1????????*/

}??????BIT;

}?????????FLMCR1;

union?{?????????????????????????????????/*?FLMCR2???????*/

unsigned?char?BYTE;???????????????/*??Byte?Access?*/

struct?{?????????????????????????????????????/*??Bit??Access?*/

unsigned?char?FLER:1;??????/*????FLER??????*/

unsigned?char?SWE2:1;??????/*????SWE2??????*/

unsigned?char?ESU2:1;??????/*????ESU2??????*/

unsigned?char?PSU2:1;??????/*????PSU2??????*/

unsigned?char?EV2?:1;??????/*????EV2???????*/

unsigned?char?PV2?:1;??????/*????PV2???????*/

unsigned?char?E2??:1;??????/*????E2????????*/

unsigned?char?P2??:1;??????/*????P2????????*/

}??????BIT;

}?????????FLMCR2;

union?{?????????????????????????????????/*?EBR1?????????*/

unsigned?char?BYTE;???????????????/*??Byte?Access?*/

struct?{??????????????????????????/*??Bit??Access?*/

unsigned?char?EB7:1;???????/*????EB7???????*/

unsigned?char?EB6:1;???????/*????EB6???????*/

unsigned?char?EB5:1;???????/*????EB5???????*/

unsigned?char?EB4:1;???????/*????EB4???????*/

unsigned?char?EB3:1;???????/*????EB3???????*/

unsigned?char?EB2:1;???????/*????EB2???????*/

unsigned?char?EB1:1;???????/*????EB1???????*/

unsigned?char?EB0:1;???????/*????EB0???????*/

}??????BIT;

}?????????EBR1;

union?{?????????????????????????????????/*?EBR2?????????*/

unsigned?char?BYTE;???????????????/*??Byte?Access?*/

struct?{??????????????????????????/*??Bit??Access?*/

unsigned?char?EB15:1;??????/*????EB15??????*/

unsigned?char?EB14:1;??????/*????EB14??????*/

unsigned?char?EB13:1;??????/*????EB13??????*/

unsigned?char?EB12:1;??????/*????EB12??????*/

unsigned?char?EB11:1;??????/*????EB11??????*/

unsigned?char?EB10:1;??????/*????EB10??????*/

unsigned?char?EB9?:1;??????/*????EB9???????*/

unsigned?char?EB8?:1;??????/*????EB8???????*/

}??????BIT;

}?????????EBR2;

};

公布自編的幾個C語言位操作函數(shù)

1?測試指定的位

unsigned?char?BitTst(unsigned?char?*Pa,char?b)//Pa為被測試的對象的地址,b值為指定的位

{

return?*Pa??(1b);

}

用法：

unsigned?char?x,y;

y=0x4F;

x=BitTst(y,3);

2?將指定的位置“1”

void?BitSet(unsigned?char?*Pa,char?b)//Pa為置位對象的地址,b值為指定的位

{

*Pa|=1b;

}

用法：BitSet(x,6);

3?將指定的位清“0”

void?BitClr(unsigned?char?*Pa,char?b)//Pa為清零位對象的地址,b值為指定的位

{

*Pa=~(1b);

}

用法：BitClr(x,6);

4?將指定的位取反

void?BitCpl(unsigned?char?*Pa,char?b)//Pa為取反位對象的地址,b值為指定的位

{

*Pa^=1b;

}