描述棧抽象數(shù)據(jù)類型的SStack接口的聲明
10年積累的網(wǎng)站制作、成都網(wǎng)站制作經(jīng)驗,可以快速應(yīng)對客戶對網(wǎng)站的新想法和需求。提供各種問題對應(yīng)的解決方案。讓選擇我們的客戶得到更好、更有力的網(wǎng)絡(luò)服務(wù)。我雖然不認識你,你也不認識我。但先網(wǎng)站制作后付款的網(wǎng)站建設(shè)流程,更有張家川回族自治免費網(wǎng)站建設(shè)讓你可以放心的選擇與我們合作。
public interfaceSStackE //棧接口
{
boolean isEmpty(); //判斷是否空棧,若空棧返回true
boolean push(E element); //元素element入棧,若操作成功返回true
E pop(); //出棧,返回當(dāng)前棧頂元素,若??辗祷豱ull
E get(); //取棧頂元素值,未出棧,若??辗祷豱ull
}
順序棧類具體操作方法的聲明:
importdataStructure.linearList.SStack;
public classSeqStackE implements SStackE
//順序棧類
{
private Object value[]; //存儲棧的數(shù)據(jù)元素
private int top; //top為棧頂元素下標(biāo)
public SeqStack(int capacity) //構(gòu)造指定容量的空棧
{
this.value = newObject[Math.abs(capacity)];
this.top=-1;
}
public SeqStack() //構(gòu)造默認容量的空棧
{
this(10);
}
public boolean isEmpty() //判斷是否空棧,若空棧返回true
{
return this.top==-1;
}
public boolean push(E element) //元素element入棧,若操作成功返回true
{
if (element==null)
return false; //空對象(null)不能入棧
if (this.top==value.length-1) //若棧滿,則擴充容量
{
Object[] temp = this.value;
this.value = newObject[temp.length*2];
for (int i=0; itemp.length;i++)
this.value[i] = temp[i];
}
this.top++;
this.value[this.top] = element;
return true;
}
public E pop() //出棧,返回當(dāng)前棧頂元素,若??辗祷豱ull
{
if (!isEmpty())
return (E)this.value[this.top--];
else
return null;
}
public E get() //取棧頂元素值,未出棧,棧頂元素未改變
{
if (!isEmpty())
return (E)this.value[this.top];
else
return null;
}
public String toString() //返回棧中各元素的字符串描述
{
String str="{";
if (this.top!=-1)
str +=this.value[this.top].toString();
for (int i=this.top-1; i=0; i--)
str += ","+this.value[i].toString();
return str+"} ";
}
實例引用public static void main(String args[])
{
SeqStackString stack = newSeqStackString(20);
System.out.print("Push: ");
char ch='a';
for(int i=0;i5;i++)
{
String str =(char)(ch+i)+"";
stack.push(str);
System.out.print(str+" ");
}
System.out.println("\n"+stack.toString());
System.out.print("Pop : ");
while(!stack.isEmpty()) //全部出棧
System.out.print(stack.pop().toString()+" ");
System.out.println();
}
public class Test {
public static void main(String[] args) {
int length = 5;
int ai = 1;
String data = "data";
String[] array = insertArrar(data, ai, length);
data = delArray(array, ai, length);
System.out.println(data);
}
public static String[] insertArrar(String data,int ai,int length){
String[] array = new String[length];
array[ai] = data;
return array;
}
public static String delArray(String[] array,int ai,int length){
String data = "";
data=array[ai];
array[ai]=null;
for(int i = 0; iarray.length;i++){
System.out.println(array[i]);
}
return data;
}
}
import java.io.IOException;
import java.util.Scanner;
public class LinkList {
private static Scanner san = new Scanner(System.in);
public static void main(String[] args) throws IOException {
List list = new List();
for (int i = 1; i = 10; i++) {
System.out.print("請輸入第" + i + "個數(shù): ");
list.add(san.nextInt());
list.print();
}
System.out.println("輸入的數(shù)據(jù)如下: ");
list.print();
}
}
class node {
int data;
node next = this; // 指向自己
}
class List {
private node header = new node();
// 循環(huán)鏈表的尾部添加數(shù)據(jù)
public node add(int data) {
node current = new node();
node temp = header;
while (temp.next != header)
temp = temp.next;
current.data = data;
current.next = temp.next;
temp.next = current;
return current;
}
// 查詢某個數(shù)字的位置 如果不在 返回-1;
public int search(int data) {
node temp = header;
int n = 0;
while (temp.next != header) {
temp = temp.next;
n++;
if (temp.data == data)
break;
}
if (temp.data == data)
return n;
else
return -1;
}
// 打印出整個鏈表
public void print() {
node temp = header;
while (temp.next != header) {
temp = temp.next;
System.out.print(temp.data + " ");
}
System.out.println();
}
// 插入數(shù)據(jù)
public node Insert(int pos, int data) {
node temp = header;
node current = new node();
for (int i = 0; i pos - 1; i++) {
if (temp.next != header) {
temp = temp.next;
} else
return null;
}
current.data = data;
if (temp.next != header) {
current.next = temp.next;
}
temp.next = current;
return current;
}
// 刪除某個數(shù)據(jù)
public node del(int data) {
node temp = header;
node oldtemp = null;
node current = null;
while (temp.next != header) {
oldtemp = temp;
temp = temp.next;
if (temp.data == data) {
current = temp;
break;
}
}
if (current == header)
return null;
oldtemp.next = current.next;
return current;
}
}
你的問題很好理解。但是你的代碼問題嚴(yán)重。
1、你想用java代碼實現(xiàn)還是c代碼實現(xiàn)?從你的代碼看是c語言
2、第一段代碼中的結(jié)構(gòu)體nod是不是應(yīng)該寫成Node?
3、inset函數(shù)中,鏈表L是有變化的,所以要用指針。結(jié)點s是不改變的,所以不應(yīng)該用指針
4、既然s不是用指針,后面的s-next自然也不能這么寫了。