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java考察代碼 JaVa代碼

java練習(xí)題求完整代碼

按照題目要求編寫的用javaBean規(guī)范設(shè)計的學(xué)生類Student的Java程序如下

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需要創(chuàng)建user.java.test包,把Student.java文件和Test.java文件放入包中,編譯Student.java文件并且編譯運行Test.java文件得到運行結(jié)果

Student.java文件代碼如下

package user.java.test;

import java.io.Serializable;

public class Student implements Serializable{

private static final long serialVersionUID = 1L;

private String no;

private String name;

private double score;

public Student(){}

public Student(String no,String name,double score){

this.no=no;

this.name=name;

this.score=score;

}

public String getNo(){ return no;}

public void setNo(String no){ this.no=no;}

public String getName(){ return name;}

public void setName(String name){ this.name=name;}

public double getScore(){ return score;}

public void setScore(double score){ this.score=score;}

public String toString(){

return "學(xué)號:"+no+",姓名:"+name+",成績:"+score;

}

public static double getAvg(Student[] sArray){

double sum=0,avg;

for(int i=0;isArray.length;i++){

sum=sum+sArray[i].getScore();

}

avg=sum/sArray.length;

return avg;

}

}

Test.java文件代碼如下

package user.java.test;

public class Test{

public static void main(String[] args){

Student[] sArray=new Student[5];

sArray[0]=new Student("001","張三",89.5);

sArray[1]=new Student("002","李四",82.5);

sArray[2]=new Student("003","王五",93);

sArray[3]=new Student("004","趙六",73.5);

sArray[4]=new Student("005","孫七",66);

System.out.println("這些學(xué)生的平均分:"+Student.getAvg(sArray));

for(int i=0;isArray.length;i++){

System.out.println(sArray[i].toString());

}

}

}

誰能幫我把這個java代碼分析一下我被繞暈了

//哈哈,感覺這道題真心好啊。不知道樓主是從哪里看到的。

//首先這道題樓主要明白以下兩點:

//1:繼承時,子類會隱藏父類相同的方法,要調(diào)用父類方法就必須使用super關(guān)鍵字。

//2:向上轉(zhuǎn)型時,子類會丟失和父類不同的方法,可以使用父類的不同名的所有方法。

public?class?PolyDemo09{

public?static?void?main(String[]?args){

A?a1?=?new?A();

A?a2?=?new?B();//B類型向上轉(zhuǎn)型丟失與A類不同方法

B?b?=?new?B();?

C?c?=?new?C();

D?d?=?new?D();

System.out.println("⑴????"?+?a1.show(b));//B類的父類是A,所以A?and?A

System.out.println("⑵????"?+?a1.show(c));?//C類父類的父類是A,D和他是同級。所以A?and?A

System.out.println("⑶????"?+?a1.show(d));//D類方法有,所以不會向上轉(zhuǎn)型,所以A?and?D

System.out.println("⑷????"?+?a2.show(b));?/*注意這時候a2的兩個方法其實是

public?String?show(D?obj)?{

return?("A?and?D");

}

public?String?show(A?obj)?{

return?("B?and?A");

}??B的父類是A,所以B?and?A?

*/

/**/???????????????????????????????????????????????????????????

System.out.println("⑸????"?+?a2.show(c));//C的父類的父類是A,所以B?and?A;

System.out.println("⑹????"?+?a2.show(d));??//D有對應(yīng)方法,所以A?and?D

System.out.println("⑺????"?+?b.show(b));?/*這個就是繼承了,繼承除了隱藏父類中和子類同名的方法外,在子類中可以直接使用父類的方法。所以B?and?B

所以就變成了

public?String?show(D?obj)?{

return?("A?and?D");

}

public?String?show(B?obj)?{

return?("B?and?B");

}

public?String?show(A?obj)?{

return?("B?and?A");

*/

System.out.println("⑻????"?+?b.show(c));?//C?的父類是B,所以B?and?B

System.out.println("⑼????"?+?b.show(d));//D有相應(yīng)方法,所以A?and?D

}

}

class?A?{

public?String?show(D?obj)?{

return?("A?and?D");

}

public?String?show(A?obj)?{

return?("A?and?A");

}

}

class?B?extends?A?{

public?String?show(B?obj)?{

return?("B?and?B");

}

public?String?show(A?obj)?{

return?("B?and?A");

}

}

class?C?extends?B?{

}

class?D?extends?B?{

}

這兩道題代碼怎么寫java?

創(chuàng)建一個名字為“ReportCard”的類,然后用下邊的內(nèi)容全部替換掉,你會成為全班最亮的仔。

import java.util.HashMap;

/**

* 學(xué)生成績單

*/

public class ReportCard {

public static void main(String[] args) {

ReportCard reportCard = new ReportCard("張三", "070602213");

reportCard.set("語文", 80.0);

reportCard.set("數(shù)學(xué)", 59.5);

reportCard.set("英語", 66.0);

reportCard.set("java", 80, 99.0);

reportCard.set("數(shù)據(jù)庫", 80, 66.0);

reportCard.set("毛概", null);

System.out.println(reportCard.getStudentName() + "語文分數(shù):" + reportCard.get("語文"));

System.out.println(reportCard.getStudentName() + "數(shù)學(xué)考核結(jié)果:" + (reportCard.isPassed("數(shù)學(xué)") ? "合格" : "不合格"));

System.out.println(reportCard.getStudentName() + "期末是否掛科:" + (reportCard.isAllPassed() ? "否" : "是"));

}

// 學(xué)生姓名

private String studentName;

// 學(xué)生學(xué)號

private String studentNumber;

// 成績單

private HashMapString, CourseResult cards = new HashMap();

public ReportCard() {

}

public ReportCard(String studentName, String studentNumber) {

this.studentName = studentName;

this.studentNumber = studentNumber;

}

public Double get(String courseName){

CourseResult courseResult = cards.get(courseName);

return courseResult == null ? Double.NaN : courseResult.getStudentScore();

}

public void set(String courseName, Double studentScore){

CourseResult courseResult = new CourseResult(courseName, studentScore);

cards.put(courseName, courseResult);

}

public void set(String courseName, double passMark, Double studentScore){

CourseResult courseResult = new CourseResult(courseName, passMark, studentScore);

cards.put(courseName, courseResult);

}

public boolean isPassed(String courseName){

return cards.get(courseName).isPassed();

}

public boolean isAllPassed(){

for(CourseResult cr : cards.values()){

if ( ! cr.isPassed()) {

return false;

}

}

return true;

}

public String getStudentName() {

return studentName;

}

public String getStudentNumber() {

return studentNumber;

}

public void setStudentName(String studentName) {

this.studentName = studentName;

}

public void setStudentNumber(String studentNumber) {

this.studentNumber = studentNumber;

}

/**

* 課程

*/

class Course{

// 課程名稱

protected String courseName;

// 及格分

protected double passMark = 60;

public Course(String courseName, Double passMark) {

this.courseName = courseName;

if ( passMark != null) {

this.passMark = passMark;

}

}

}

/**

* 課程成績

*/

class CourseResult extends Course{

// 學(xué)生成績

private Double studentScore;

public CourseResult(String courseName, Double studentScore) {

this(courseName, null, studentScore);

}

public CourseResult(String courseName, Double passMark, Double studentScore) {

super(courseName, passMark);

this.studentScore = studentScore == null ? Double.NaN : studentScore;

}

public boolean isPassed(){

return studentScore = passMark;

}

public String getCourseName() {

return courseName;

}

public double getPassMark() {

return passMark;

}

public Double getStudentScore() {

return studentScore;

}

}

java問題。求解代碼

public?class?test1{

int?counter=0;

public?static?void?main(String[]args){

int?count=0;

test1[]m4a=new?test1[20];

int?x=0;

while(x9)

{

//由于counter不是static的,所以每次new?test1()的時候,counter均為0

m4a[x]=new?test1();

//所以這里m4a[0]到m4a[8]的counter均為1

m4a[x].counter=m4a[x].counter+1;

//這里一共被加了九次?沒懸念吧因為循環(huán)了九次

count=count+1;

//這里函數(shù)進去,在??5的時候?返回了1,大于等于5的時候返回0,所以這里一共被加了5次,沒懸念吧

count=count+m4a[x].maybeNew(x);

x=x+1;

}

//所以這里出現(xiàn)的結(jié)果就是?9+5=14??和?1

System.out.println(count+"?"+m4a[1].counter);

}

public?int?maybeNew(int?index)

{

if(index5)

{

test1?m4=new?test1();

m4.counter=m4.counter+1;

return?1;

}

return?0;

}

}


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