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vb.net右移位 vb 位移

你好,請教一下vb.net中想實(shí)現(xiàn)標(biāo)簽自動(dòng)從左到右移動(dòng)如何實(shí)現(xiàn),我是新手

見下面代碼,放置定時(shí)器,按鈕,標(biāo)簽各一個(gè)

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Public?Class?Form1

Private?Sub?Timer1_Tick(ByVal?sender?As?System.Object,?ByVal?e?As?System.EventArgs)?Handles?Timer1.Tick?'定時(shí)器

If?Label1.Right??Me.Width?Then

Label1.Left?+=?10'移動(dòng)距離

Else

Label1.Left?=?0

End?If

End?Sub

Private?Sub?Button1_Click(ByVal?sender?As?System.Object,?ByVal?e?As?System.EventArgs)?Handles?Button1.Click?'開啟或者關(guān)閉定時(shí)器

Timer1.Interval?=?1000?'1秒

If?Timer1.Enabled?=?False?Then

Timer1.Start()?'開定時(shí)器

Else

Timer1.Stop()?'關(guān)定時(shí)器

End?If

End?Sub

End?Class

vb.net實(shí)現(xiàn)控件自由移動(dòng)

Dim i As Integer

For i = 0 To Me.Width - Button1.Width 'me為容器,典型的是form1

Button1.Left += 1

Windows.Forms.Application.DoEvents()

Next

原理:不斷地變化button1的X軸,使其向右移,同樣,只要控制好其x,y軸,就可以變化button的變化

如果是做小游戲,建議弄成類吧,把其中的左(右)移或?qū)瞧渌苿?dòng)弄成其接口,以便操作。

由于涉及內(nèi)容太多,不再詳述。原理都一樣

用vb.net編寫項(xiàng)目移動(dòng)。。。求高人指點(diǎn)。。。。

窗體是指由兩個(gè)列表框(ListBox1、ListBox2)和4個(gè)命令按鈕(Button1“”按鈕,Button2“”按鈕,Button3“”按鈕,Button4“”按鈕)所構(gòu)成的界面,代碼:

Public Class Form1

Private Sub Form1_Load(sender As System.Object, e As System.EventArgs) Handles MyBase.Load

Me.Text = "選項(xiàng)移動(dòng)"

ListBox1.SelectionMode = SelectionMode.MultiSimple

ListBox2.SelectionMode = SelectionMode.One

For i = 1 To 10

ListBox1.Items.Add(Chr(Asc("a") + i - 1))

Next

For i = 1 To 10

ListBox2.Items.Add(i.ToString)

Next

End Sub

Private Sub Button1_Click(sender As System.Object, e As System.EventArgs) Handles Button1.Click

If ListBox1.SelectedItems Is Nothing Then Exit Sub

Dim b As ListBox.ObjectCollection

For i = 0 To Me.ListBox1.SelectedItems.Count - 1

Me.ListBox2.Items.Add(Me.ListBox1.SelectedItems(0))

Me.ListBox1.Items.RemoveAt(Me.ListBox1.SelectedIndices(0))

Next

End Sub

Private Sub Button3_Click(sender As System.Object, e As System.EventArgs) Handles Button3.Click

If ListBox2.SelectedItems IsNot Nothing Then

ListBox1.Items.Add(ListBox2.SelectedItem)

ListBox2.Items.Remove(ListBox2.SelectedItem)

End If

End Sub

Private Sub Button2_Click(sender As System.Object, e As System.EventArgs) Handles Button2.Click

For Each itm As Object In ListBox1.Items

ListBox2.Items.Add(itm)

Next

ListBox1.Items.Clear()

End Sub

Private Sub Button4_Click(sender As System.Object, e As System.EventArgs) Handles Button4.Click

For Each itm As Object In ListBox2.Items

ListBox1.Items.Add(itm)

Next

ListBox2.Items.Clear()

End Sub

End Class

vb.net 1

1左移10位,1后面加10個(gè)0

結(jié)果就是:10000000000

五、按位運(yùn)算符

注意不能在VB.Net中直接使用以下二進(jìn)制數(shù),使用時(shí)需轉(zhuǎn)換為相應(yīng)的十六或十進(jìn)制數(shù)字。

1. 表示按位左移,空缺處補(bǔ)0。如:101101 2 結(jié)果為 110100

2. 表示按位右移,如:101101 2 結(jié)果為 001011

請問VB中怎么能向右循環(huán)一位

VB程序中實(shí)現(xiàn)字節(jié)移位操作

在利用VB系統(tǒng)開發(fā)數(shù)據(jù)采集或工業(yè)控制軟件,或?qū)ξ募M(jìn)行低級操作時(shí),常需要對字節(jié)進(jìn)行移位操作,但VB系統(tǒng)中沒有提供字節(jié)移位操作的指令和函數(shù),只提供了And(與)、Or(或)、Xor(異或)、Equ(同或)、Not(非)等幾個(gè)邏輯運(yùn)算指令。筆者在用VB系統(tǒng)開發(fā)工業(yè)控制軟件的過程中,就遇到了這個(gè)問題,于是利用VB中已有的邏輯運(yùn)算指令,模擬匯編語言的字節(jié)移位指令,編制了七個(gè)字節(jié)移位函數(shù):邏輯左移、邏輯右移、算術(shù)右移、循環(huán)左移、循環(huán)右移、進(jìn)位循環(huán)左移和進(jìn)位循環(huán)右移。

在匯編語言指令中,邏輯左移的功能相當(dāng)于乘2, 邏輯右移的功能相當(dāng)于除2,利用這個(gè)特性,在VB程序中用乘2和除2方法實(shí)現(xiàn)位的左移和右移,然后再用And(與)和Or(或)邏輯運(yùn)算指令,判斷移位過程中是否有進(jìn)位發(fā)生,將進(jìn)行標(biāo)志置位。

程序清單

CF是進(jìn)位標(biāo)志,采用Boolean類型邏輯變量,如果CF為True表示有進(jìn)位,為False則表示無進(jìn)位。

Public CF As Boolean '進(jìn)位標(biāo)志

'1.邏輯左移

Public Function SHL(OPR As Byte, n As Integer) As Byte

Dim BD As Byte

Dim I As Integer

BD = OPR

For i = 1 To n - 1

BD = (BD And H7F) * 2 '將D7位屏蔽左移,防止字節(jié)溢出

Next i

CF = BD And H80 '判斷D7位是否進(jìn)位

SHL = (BD And H7F) * 2

End Function

'2.邏輯右移

Public Function SHR(OPR As Byte, n As Integer) As Byte

Dim BD As Byte

Dim I As Integer

BD = OPR

For i = 1 To n - 1

BD = BD \ 2 '右移

Next i

CF = BD And 1 '判斷D0位是否進(jìn)位

SHR = BD \ 2

End Function

'3.算術(shù)右移

Public Function SAR(OPR As Byte, n As Integer) As Byte

Dim BD As Byte

Dim I As Integer

Dim Fg1 As Byte

BD = OPR

Fg1 = BD And H80

For i = 1 To n - 1

BD = BD \ 2 '右移

Next i

CF = BD And 1 '判斷D0位是否進(jìn)位

BD = BD \ 2 '右移

SAR = BD Or Fg1

End Function

'4.循環(huán)左移

Public Function ROL(OPR As Byte, n As Integer) As Byte

Dim BD As Byte

Dim I As Integer

Dim Fg1 As Byte

BD = OPR

For i = 1 To n

Fg1 = (BD And H80) \ 128 '判斷D7位是否進(jìn)位

BD = ((BD And H7F) * 2) Or Fg1 '帶進(jìn)位左移

Next i

CF = Fg1

ROL = BD

End Function

'5.循環(huán)右移

Public Function ROR(OPR As Byte, n As Integer) As Byte

Dim BD As Byte

Dim I As Integer

Dim Fg1 As Byte

Dim Fg2 As Byte

BD = OPR

For i = 1 To n

Fg1 = (BD And 1) * 128 '判斷D0位是否進(jìn)位

BD = (BD \ 2) Or Fg1 '帶進(jìn)位右移

Next i

CF = Fg1

ROR = BD

End Function

'6.進(jìn)位循環(huán)左移

Public Function RCL(OPR As Byte, n As Integer) As Byte

Dim BD As Byte

Dim I As Integer

Dim Fg1 As Byte

Dim Fg2 As Byte

BD = OPR

Fg2 = CF And 1

For i = 1 To n

Fg1 = (BD And H80) \ 128 '判斷D7位是否進(jìn)位

BD = ((BD And H7F) * 2) Or Fg2 '帶進(jìn)位左移

Fg2 = Fg1

Next i

CF = Fg1

RCL = BD

End Function

'7.進(jìn)位循環(huán)右移

Public Function RCR(OPR As Byte, n As Integer) As Byte

Dim BD As Byte

Dim I As Integer

Dim Fg1 As Byte

Dim Fg2 As Byte

BD = OPR

Fg2 = CF And 128

For i = 1 To n

Fg1 = (BD And 1) * 128 '判斷D0位是否進(jìn)位

BD = (BD \ 2) Or Fg2 '帶進(jìn)位右移

Fg2 = Fg1

Next i

CF = Fg1

RCR = BD

End Function

結(jié)束語

以上七個(gè)字節(jié)移位操作函數(shù)的功能和用法同宏匯編語言的移位操作指令基本相同,不過只對單字節(jié)進(jìn)行操作,但上述程序稍加改動(dòng)后,就可對雙字節(jié)Integer類型和四字節(jié)Long類型進(jìn)行移位操作。


名稱欄目:vb.net右移位 vb 位移
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