今天就跟大家聊聊有關(guān)SQL中怎么查詢(xún)重復(fù)記錄,可能很多人都不太了解,為了讓大家更加了解,小編給大家總結(jié)了以下內(nèi)容,希望大家根據(jù)這篇文章可以有所收獲。
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1、查找表中多余的重復(fù)記錄,重復(fù)記錄是根據(jù)單個(gè)字段(peopleId)來(lái)判斷復(fù)制代碼 代碼如下: select * from peoplewhere peopleId in (select peopleId from people group by peopleId having count
(peopleId) > 1)
2、刪除表中多余的重復(fù)記錄,重復(fù)記錄是根據(jù)單個(gè)字段(peopleId)來(lái)判斷,只留有rowid最小的記錄復(fù)制代碼 代碼如下: delete from people where peopleId in (select peopleId from people group by peopleId having count
(peopleId) > 1)and rowid not in (select min(rowid) from people group by peopleId having count(peopleId
)>1)
3、查找表中多余的重復(fù)記錄(多個(gè)字段)復(fù)制代碼 代碼如下: select * from vitae awhere (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having
count(*) > 1)
4、刪除表中多余的重復(fù)記錄(多個(gè)字段),只留有rowid最小的記錄復(fù)制代碼 代碼如下: delete from vitae awhere (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having
count(*) > 1)and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
5、查找表中多余的重復(fù)記錄(多個(gè)字段),不包含rowid最小的記錄復(fù)制代碼 代碼如下: select * from vitae awhere (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having
count(*) > 1)and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
(二)比方說(shuō)在A表中存在一個(gè)字段“name”,而且不同記錄之間的“name”值有可能會(huì)相同,現(xiàn)在就是需要查詢(xún)出在該表中的各記錄之間,“name”值存在重復(fù)的項(xiàng);復(fù)制代碼 代碼如下: Select Name,Count(*) From A Group By Name Having Count(*) > 1
如果還查性別也相同大則如下:復(fù)制代碼 代碼如下: Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1
(三)方法一復(fù)制代碼 代碼如下: declare @max integer,@id integerdeclare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having
count(*) >; 1open cur_rowsfetch cur_rows into @id,@maxwhile @@fetch_status=0beginselect @max = @max -1set rowcount @maxdelete from 表名 where 主字段 = @idfetch cur_rows into @id,@maxendclose cur_rowsset rowcount 0
方法二
有兩個(gè)意義上的重復(fù)記錄,一是完全重復(fù)的記錄,也即所有字段均重復(fù)的記錄,二是部分關(guān)鍵字段重
復(fù)的記錄,比如Name字段重復(fù),而其他字段不一定重復(fù)或都重復(fù)可以忽略。
1、對(duì)于第一種重復(fù),比較容易解決,使用復(fù)制代碼 代碼如下: select distinct * from tableName
就可以得到無(wú)重復(fù)記錄的結(jié)果集。
如果該表需要?jiǎng)h除重復(fù)的記錄(重復(fù)記錄保留1條),可以按以下方法刪除復(fù)制代碼 代碼如下: select distinct * into #Tmp from tableNamedrop table tableNameselect * into tableName from #Tmpdrop table #Tmp
發(fā)生這種重復(fù)的原因是表設(shè)計(jì)不周產(chǎn)生的,增加唯一索引列即可解決。
2、這類(lèi)重復(fù)問(wèn)題通常要求保留重復(fù)記錄中的第一條記錄,操作方法如下
假設(shè)有重復(fù)的字段為Name,Address,要求得到這兩個(gè)字段唯一的結(jié)果集復(fù)制代碼 代碼如下: select identity(int,1,1) as autoID, * into #Tmp from tableNameselect min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoIDselect * from #Tmp where autoID in(select autoID from #tmp2)
最后一個(gè)select即得到了Name,Address不重復(fù)的結(jié)果集(但多了一個(gè)autoID字段,實(shí)際寫(xiě)時(shí)可以寫(xiě)
在select子句中省去此列)
(四)查詢(xún)重復(fù)復(fù)制代碼 代碼如下: select * from tablename where id in (select id from tablename group by id having count(id) > 1)
看完上述內(nèi)容,你們對(duì)SQL中怎么查詢(xún)重復(fù)記錄有進(jìn)一步的了解嗎?如果還想了解更多知識(shí)或者相關(guān)內(nèi)容,請(qǐng)關(guān)注創(chuàng)新互聯(lián)行業(yè)資訊頻道,感謝大家的支持。