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mysql查詢本季度
今天
select * from 表名 where to_days(時間字段名) = to_days(now());
昨天
SELECT *FROM表名WHERE TO_DAYS( NOW( ) ) – TO_DAYS( 時間字段名) <= 1
7天
SELECT *FROM表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(時間字段名)
近30天
SELECT *FROM表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(時間字段名)
本月
SELECT *FROM表名 WHERE DATE_FORMAT( 時間字段名, ‘%Y%m’ ) = DATE_FORMAT( CURDATE( ) , ‘%Y%m’ )
上一月
SELECT *FROM表名 WHERE PERIOD_DIFF( date_format( now( ) , ‘%Y%m’ ) , date_format( 時間字段名, ‘%Y%m’ ) ) =1
#查詢本季度數(shù)據(jù) select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now()); #查詢上季度數(shù)據(jù) select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER)); #查詢本年數(shù)據(jù) select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW()); #查詢上年數(shù)據(jù) select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));
查詢當前這周的數(shù)據(jù) SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,’%Y-%m-%d’)) = YEARWEEK(now());
查詢上周的數(shù)據(jù) SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,’%Y-%m-%d’)) = YEARWEEK(now())-1;
查詢當前月份的數(shù)據(jù) select name,submittime from enterprisewhere date_format(submittime,’%Y-%m’)=date_format(now(),’%Y-%m’)
查詢距離當前現(xiàn)在6個月的數(shù)據(jù) select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();
查詢上個月的數(shù)據(jù) select name,submittime from enterprisewhere date_format(submittime,’%Y-%m’)=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),’%Y-%m’)
select*from`user`whereDATE_FORMAT(pudate,‘%Y%m‘)=DATE_FORMAT(CURDATE(),‘%Y%m‘) ; select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,’%y-%m-%d’)) = WEEKOFYEAR(now())
select* fromuser whereMONTH(FROM_UNIXTIME(pudate,‘%y-%m-%d‘))=MONTH(now())
select* from[user] whereYEAR(FROM_UNIXTIME(pudate,‘%y-%m-%d‘))=YEAR(now()) andMONTH(FROM_UNIXTIME(pudate,‘%y-%m-%d‘))=MONTH(now())
select* from[user] wherepudatebetween上月最后一天 and下月第一天
wheredate(regdate)=curdate();
select*fromtestwhereyear(regdate)=year(now())andmonth(regdate)=month(now())andday(regdate)=day(now())
SELECT date( c_instime ) ,curdate( )FROM `t_score`WHERE 1LIMIT 0 , 30
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