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java中數(shù)據(jù)庫的面試題有哪些

本篇內(nèi)容介紹了“java中數(shù)據(jù)庫的面試題有哪些”的有關(guān)知識,在實際案例的操作過程中,不少人都會遇到這樣的困境,接下來就讓小編帶領(lǐng)大家學(xué)習(xí)一下如何處理這些情況吧!希望大家仔細(xì)閱讀,能夠?qū)W有所成!

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基本表結(jié)構(gòu):

        student(sno,sname,sage,ssex)學(xué)生表
        course(cno,cname,tno) 課程表
        sc(sno,cno,score) 成績表

        teacher(tno,tname) 教師表

111、把“sc”表中“王五”所教課的成績都更改為此課程的平均成績
update sc set score = (select avg(sc_2.score) from sc sc_2 wheresc_2.cno=sc.cno)
from course,teacher where course.cno=sc.cno and course.tno=teacher.tno andteacher.tname='王五'


112、查詢和編號為2的同學(xué)學(xué)習(xí)的課程完全相同的其他同學(xué)學(xué)號和姓名
這一題分兩步查:

1,

select sno
from sc
where sno <> 2
group by sno
having sum(cno) = (select sum(cno) from sc where sno = 2)

2,
select b.sno, b.sname
from sc a, student b
where b.sno <> 2 and a.sno = b.sno
group by b.sno, b.sname
having sum(cno) = (select sum(cno) from sc where sno = 2)


113、刪除學(xué)習(xí)“王五”老師課的sc表記錄
delete sc from course, teacher
where course.cno = sc.cno and course.tno = teacher.tno and tname = '王五'


114、向sc表中插入一些記錄,這些記錄要求符合以下條件:
將沒有課程3成績同學(xué)的該成績補齊, 其成績?nèi)∷袑W(xué)生的課程2的平均成績

insert sc select sno, 3, (select avg(score) from sc where cno = 2)
from student
where sno not in (select sno from sc where cno = 3)


115、按平平均分從高到低顯示所有學(xué)生的如下統(tǒng)計報表:
-- 學(xué)號,企業(yè)管理,馬克思,UML,數(shù)據(jù)庫,物理,課程數(shù),平均分

select sno as 學(xué)號
,max(case when cno = 1 then score end) AS 企業(yè)管理
,max(case when cno = 2 then score end) AS 馬克思
,max(case when cno = 3 then score end) AS UML
,max(case when cno = 4 then score end) AS 數(shù)據(jù)庫
,max(case when cno = 5 then score end) AS 物理
,count(cno) AS 課程數(shù)
,avg(score) AS 平均分
FROM sc
GROUP by sno
ORDER by avg(score) DESC


116、查詢各科成績最高分和最低分:

以如下形式顯示:課程號,最高分,最低分
select cno as 課程號, max(score) as 最高分, min(score) 最低分
from sc group by cno

select  course.cno as '課程號'
,MAX(score) as '最高分'
,MIN(score) as '最低分'
from sc,course
where sc.cno=course.cno
group by course.cno


117、按各科平均成績從低到高和及格率的百分?jǐn)?shù)從高到低順序
SELECT t.cno AS 課程號,
max(course.cname)AS 課程名,
isnull(AVG(score),0) AS 平均成績,
100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/count(1) AS 及格率
FROM sc t, course
where t.cno = course.cno
GROUP BY t.cno
ORDER BY 及格率 desc


118、查詢?nèi)缦抡n程平均成績和及格率的百分?jǐn)?shù)(用"1行"顯示):

企業(yè)管理(001),馬克思(002),UML (003),數(shù)據(jù)庫(004)
select 
avg(case when cno = 1 then score end) as 平均分1,
avg(case when cno = 2 then score end) as 平均分2,
avg(case when cno = 3 then score end) as 平均分3,
avg(case when cno = 4 then score end) as 平均分4,
100 * sum(case when cno = 1 and score > 60 then 1 else 0 end) / sum(casewhen cno = 1 then 1 else 0 end) as 及格率1,
100 * sum(case when cno = 2 and score > 60 then 1 else 0 end) / sum(casewhen cno = 2 then 1 else 0 end) as 及格率2,
100 * sum(case when cno = 3 and score > 60 then 1 else 0 end) / sum(casewhen cno = 3 then 1 else 0 end) as 及格率3,
100 * sum(case when cno = 4 and score > 60 then 1 else 0 end) / sum(casewhen cno = 4 then 1 else 0 end) as 及格率4
from sc


119、查詢不同老師所教不同課程平均分, 從高到低顯示
select max(c.tname) as 教師, max(b.cname) 課程, avg(a.score) 平均分
from sc a, course b, teacher c
where a.cno = b.cno and b.tno = c.tno
group by a.cno
order by 平均分 desc

或者:
select r.tname as '教師',r.rname as '課程' , AVG(score) as '平均分'
from sc,
(select  t.tname,c.cno as rcso,c.cname as rname
from teacher t ,course c
where t.tno=c.tno)r
where sc.cno=r.rcso
group by sc.cno,r.tname,r.rname 
order by AVG(score) desc


120、查詢?nèi)缦抡n程成績均在第3名到第6名之間的學(xué)生的成績:
-- [學(xué)生ID],[學(xué)生姓名],企業(yè)管理,馬克思,UML,數(shù)據(jù)庫,平均成績

select top 6 max(a.sno) 學(xué)號, max(b.sname) 姓名,
max(case when cno = 1 then score end) as 企業(yè)管理,
max(case when cno = 2 then score end) as 馬克思,
max(case when cno = 3 then score end) as UML,
max(case when cno = 4 then score end) as 數(shù)據(jù)庫,
avg(score) as 平均分
from sc a, student b
where a.sno not in

(select top 2 sno from sc where cno = 1 order by score desc)
  and a.sno not in (select top 2 sno from sc where cno = 2 order by scoredesc)
  and a.sno not in (select top 2 sno from sc where cno = 3 order by scoredesc)
  and a.sno not in (select top 2 sno from sc where cno = 4 order by scoredesc)
  and a.sno = b.sno
group by a.sno

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