題單傳送門

為甘孜州等地區(qū)用戶提供了全套網(wǎng)頁設(shè)計(jì)制作服務(wù)，及甘孜州網(wǎng)站建設(shè)行業(yè)解決方案。主營業(yè)務(wù)為網(wǎng)站制作、網(wǎng)站設(shè)計(jì)、甘孜州網(wǎng)站設(shè)計(jì)，以傳統(tǒng)方式定制建設(shè)網(wǎng)站，并提供域名空間備案等一條龍服務(wù)，秉承以專業(yè)、用心的態(tài)度為用戶提供真誠的服務(wù)。我們深信只要達(dá)到每一位用戶的要求，就會(huì)得到認(rèn)可，從而選擇與我們長期合作。這樣，我們也可以走得更遠(yuǎn)！卡片

#include#include 
#include#includeusing namespace std;

int main(){int cnt[15] = {0};
	int num = 0;
	while(++num){int t = num;
		while(t){	cnt[t % 10]++;
			if(cnt[t % 10] >2021){		cout<< num - 1<< endl;
				return 0;
			}
			t /= 10;
		}
	}
	return 0;
}

直線

#include#include 
#include#include#includeusing namespace std;
typedef pairPDD;

int main() {vectorv;
	for (int x1 = 0; x1< 20; ++x1)
		for (int y1 = 0; y1< 21; ++y1)
			for (int x2 = 0; x2< 20; ++x2)
				for (int y2 = 0; y2< 21; ++y2) {if (x1 != x2) {double k = 1.0 * (y2 - y1) / (x2 - x1);
						double b = y1 - k * x1;
						v.push_back({k, b});
					}
				}
	sort(v.begin(), v.end());
	int ans = 1;
	for (int i = 1; i< v.size(); ++i) {if (v[i].first - v[i - 1].first >1e-8 || v[i].second - v[i - 1].second >1e-8) {	ans++;
		}
	}
	cout<< ans + 20<< endl;
	return 0;
}

貨物擺放

#include#include 
#include#includeusing namespace std;
typedef long long LL;

int main() {LL n = 2021041820210418;
	LL ans = 0;
	for (LL i = 1; i<= n / i; ++i) {if (n % i != 0) continue;
		LL t = n / i;
		for (LL j = i; j<= t / j; ++j) {	if (t % j != 0) continue;
			LL k = t / j;
			if (k< j || i >j)  continue;
			if (i == j && i == k) ans += 1;
			else if (i == j || i == k || j == k) ans += 3;
			else ans += 6;
		}
	}
	cout<< ans<< endl;
	return 0;
}

路徑

#include#include 
#include#includeusing namespace std;
typedef long long LL;

LL f[3000];

int gcd(int a, int b){return b ? gcd(b, a % b) : a;
}

int main() {memset(f, 0x3f, sizeof f);
	f[1] = 0;
	for(int i = 2; i<= 2021; ++i){int l = max(1, i - 21);
		for(int j = l; j< i; ++j){	f[i] = min(f[i], f[j] + 1ll * (i * j) / gcd(i, j));
		}
	}
	cout<< f[2021]<< endl;
	return 0;
}

空間

#include#include 
#include#includeusing namespace std;

int main() {cout<< 256 * 1024 * 1024 / 4<< endl;
	return 0;
}

砝碼稱重

#include#include 
#include#includeusing namespace std;
typedef long long LL;
const int N = 110, M = 1e5 + 10;

int dp[N][M], w[N];

int main(){int n;
	cin >>n;
	int sum = 0;
	for(int i = 1; i<= n; ++i){cin >>w[i];
		sum += w[i];
	}
	dp[0][0] = 1;
	for(int i = 1; i<= n; ++i){for(int j = 0; j<= sum; ++j){	dp[i][j] = dp[i - 1][abs(j - w[i])] + dp[i - 1][j + w[i]] + dp[i - 1][j];
		}
	}
	int ans = 0;
	for(int i = 1; i<= sum; ++i){if (dp[n][i] != 0) {	ans++;
		}
	}
	cout<< ans<< endl;
	return 0;
}

括號(hào)序列

#include#include 
#include#includeusing namespace std;
typedef long long LL;
const int N = 5e3 + 10, mod = 1e9 + 7;

int f[N][N], n;
string s;

LL get() {memset(f, 0, sizeof(f));
	f[0][0] = 1;
	
	for (int i = 1; i<= n; i++) {if (s[i - 1] == '(' ) {	for (int j = 1; j<= n; j++)
				f[i][j] = f[i - 1][j - 1];
		} 
		else {	f[i][0] = (f[i - 1][1] + f[i - 1][0]) % mod;
			for (int j = 1; j<= n; j++)
				f[i][j] = (f[i - 1][j + 1] + f[i][j - 1]) % mod;
		}
	}
	
	for (int i = 0; i<= n; i++)
		if (f[n][i]) return f[n][i];
		
	return -1;
}

int main(){cin >>s;
	n = s.length();
	LL x = get();
	reverse(s.begin(), s.end());
	for (int i = 0; i< n; i++) {if (s[i] == ')') s[i] = '(';
		else s[i] = ')';
	}
	LL y = get();
	cout<< (x * y) % mod<< endl;
	return 0;
}

時(shí)間顯示

#include#include 
#include#includeusing namespace std;

int main(){long long n;
	int t;
	cin >>t;
	for(int i = 1; i<= t; i++)
	{cin >>n;
		n /= 1000;
		n %= 24 * 60 * 60;
		printf("%02d:%02d:%02d\n", n / 60 / 60, n / 60 % 60, n % 60);
	}
	return 0;
}

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